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40 B 8 T 6 M 3 K 4=> 40 ÷ 8 – 6 + 3 × 4=> 5 – 6 + 12=> 17 – 6 = 11Hence, option B is the correct response.
Alternative Method: Lcm of 9 , 18 = 18 A does = 18/9 = 2 unit/dayB does = 18/18 = 1 unit/daysTotal Work completed by both = 18/3 = 6 days.But B leave 2 days before the completion of the work.So A + B) 4 days work = 3 unit x 4 = 12 work then Remaining work = 6 which will be done by only A = 6/ 2 = 3 days Total Days = 4 days + 3 days = 7 daysDetailed Methods: The work was scheduled to be completed in = 6 days. Since, B left 2 days before scheduled completion; He worked for 4 days only. Let the number of days A worked be ‘x’. Now, = 1. On Solving, we get x = 7 days.
Or If we solve it using efficiency method.
work done by A in 9 days = work done by B in 18 daysAx9 = Bx18A = 2BWe can say that efficiency of A is two time of efficiency of B.Let efficiency of B is 1, then efficiency of A is 2.So, total work = 9 x2 or 18x1 = 18If they work together, total efficiency is 3So, scheduled time = 18/3 = 6 days,But B left 2 days before scheduled time. It means 2 days work of B will be done by A.work of 2 days of B = 2x1 = 2 unit2 unit of work can be done by A in 1 day.Hence, total time will be 7 days.
Directions For Questions
In the sentence, identify the segment which contains the grammatical error. If the sentence has no error, then select 'No error'.
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There is an error in the second option as the use of "that" is incorrect in the sentence. Churchill has mentioned a specific event in his book. To make something specific or definite, we use the article "the". So, "that" should be omitted.
In the sentence identify the segment which contains the grammatical error. If the sentence has no error, then select 'No error'.
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