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SSC CHSL 2019-20 Aptitude Test - 31
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SSC CHSL 2019-20 Aptitude Test - 31

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  • Question 1/10
    1 / -0

    If sin θ + cos θ = 1, then what is the value of Sin θ cos θ ?

    Solutions

     

  • Question 2/10
    1 / -0

    Difference of two numbers is 1600 . If 0.75% of A is equal to 1.25% of B, then what are the values of A and B respectively .

    Solutions

    0.75 A = 1.25 B

    A/B = 5/3

    A - B = 5 – 3 = 2 represents 1600, therefore 1 represents 800

    A = 800×5 = 4000

    B = 800×3 = 2400

     

  • Question 3/10
    1 / -0

    A reduction of 10% in the price of rice allow a family to buy 8 kg more for Rs. 272. What is the reduced price per kilogram of rice?

    Solutions

     

  • Question 4/10
    1 / -0

    If the sum of x and its reciprocal is 2, what is the value of (x17 + 1/x19) ?

    Solutions

     

  • Question 5/10
    1 / -0

    The volume of a right circular cone, with a base radius the same as its altitude, and the volume of a hemisphere are equal. The ratio of the radii of the cone to the hemisphere is:

    Solutions

     

  • Question 6/10
    1 / -0

    A motor-boat goes 49 km downstream in 14 hours and 5 km upstream in 2 hours. Find the speed of motor-boat.

    Solutions

    Let the speed of motor-boat in still water is A km/hr while the speed of the stream is B km/hr.
    Case-I:
    14(A + B) = 49
    A + B = 3.5 ……….(i)
    Case-II:
    2(A – B) = 5
    A – B = 2.5 ……….(ii)
    Solving equation (i) and (ii)
    2A = 6
    A = 3 km/hr

     

  • Question 7/10
    1 / -0

    The selling price of an item inclusive of a 10% profit was ₹440. What would be the percentage loss if the item was sold for ₹370?

    Solutions

    Selling Price = Cost Price + Profit

    440 = Cost Price + 10% Profit

    Profit is calculated on Cost Price. Given, profit is 10%. So, selling price becomes 110% of cost price.

    110% = 440

    100% = 400

    Cost Price = 400

    New Seling Price = 370

    Loss = CP –SP

    Loss = 400 – 370 = 30

    Loss% = (Loss/Cost Price) x 100

    Loss% = (30/400) x100

    Loss% = 7.5%

     

  • Question 8/10
    1 / -0

    Which one of the following is a prime number?

    Solutions

    161 is divisible by 7 & 23

    171 is divisible by 3

    173 is a prime number

    221 is divisible by 13 & 17

     

  • Question 9/10
    1 / -0

    The average marks of 138 students is 65 and the average marks of 69 students of another class is 68. What will be the average if both the classes are merged?

    Solutions

    Average =  (138×65 + 69×68)/ (138+69) = 66

    Average =  (138×65 + 69×68)/ (138+69) = 66

     

  • Question 10/10
    1 / -0

    Krish is 5 years younger than Parthiv. Eight years ago three times the age of Krish was 10 more than twice the age of Parthiv. Find Krish’s present age.

    Solutions

    Let Krish’s present age be x.

    Then Parthiv’s present age is x+5.

    It is given that 8 years ago three times the age of Krish was 10 more than twice the age of Parthiv.

    So, 
    ⇒ 3(x - 8) = 10 + 2 (x + 5 - 8)

    ⇒ 3x - 24 = 10 + 2(x - 3)

    ⇒ x = 28.

     

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