Sum of supplementary = 180Â

4y + 55Â + 3y + 69Â = 180Â

7y + 124 Â = 180Â

7y = 180Â - 124Â

7y = 56

y = 56/7

y = 8

Option B is correct.

There are total 4 slant surfaces on the pyramid.

Thus, Total surface area = Lateral Surface Area + Area of Base

⇒ 32 = (½ × Base Perimeter × Slant Height) + Area of square base

⇒ 32 = (½ × 4a × 7) + a²

⇒ a² + 14a – 32 = 0

⇒ a² + 16a – 2a – 32 = 0

⇒ a(a + 16) – 2(a + 16) = 0

⇒ a = -16, +2

Thus, side of the base = a = 2 cm

Area of square base = 2×2 = 4 cm²

Lateral surface area = (½ × 4a × 7) = ½ × 8 × 7 = 28 cm²

Required ratio

= 7 : 1.

In case of infinitives in a sentence, ‘to + V₁’ is changed to ‘to + be +V₃’ in the passive voice.

Here, ‘to squander’ must be changed to ‘to be squandered’ in the passive voice.

Thus, the correct sentence will be option D i.e. ‘They have no time available nor money to be squandered on what they consider to be pointless pursuits.’

Radius of small spherical balls = 0.7 cm

Diameter of cylindrical container = 7 cm

Radius of cylindrical container = 7/2 cm

Let number of spherical balls that dropped into a cylindrical container =k

Volume of k spherical balls that are dropped = Volume of cylindrical container up to 5.6 cm

⇒

⇒ k = 150

The given sentence is in the Active voice, as the form of the verb (‘is climbing’) shows that its subject (‘boy’) was doing something and was ‘active’.

Therefore, it must be changed to the Passive voice, where something could be done by the subject, and it was ‘passive’.

In order to do that,

1. The object of the transitive verb in the Active voice should become the subject of the verb in the Passive voice (‘cliff’ becomes the subject in place of ‘boy’).

2. Add the appropriate form of the verb 'be' to the sentence and use the past participle of the verb (‘is climbing’ is converted to ‘is being climbed’).

3. Add a 'by' followed by the doer of the action.

Thus, the same sentence in the Passive voice is ‘The cliff is being climbed by the boy’.

Hence, option C is the correct answer.

PQ = 20 m

AB = 15 m

PR = 20-15 =5 m

Distance between top of poles AP = √(12² + 5²) = 13m