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SSC CGL 2019 Aptitude Test - 34
Result
SSC CGL 2019 Aptitude Test - 34

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  • Question 1/10
    1 / -0

    If x^3+4x-8=0 then x^7+64x^2+2=?

    Solutions

     

  • Question 2/10
    1 / -0

    Solutions

     

  • Question 3/10
    1 / -0

    If α and β are the roots of the equation x2+x+1=0  then find the quadratic equation having roots

    Solutions

    Given equation

    x^2+x+1=0

    α+β=-1& αβ=1

    α+1/α=-1

     α^3+1/α^3 =(-1)^3-3(-1)=2

    α^3+β^3=2

    eq can be written as x2-2x+1=0

     

  • Question 4/10
    1 / -0

    Solutions

     

  • Question 5/10
    1 / -0

    In the given figure, PQRS is a square of side 12 cm. A line RT is drawn in as shown in figure. If diameter of smaller circle is 6cm, then find the diameter of the bigger circle ?

    Solutions

     

  • Question 6/10
    1 / -0

    I and O are respectively the incentre and circumcentre of a triangle ABC.The line AI produced intersects the circumcircle of ∆ ABC at the point D.

    If ∠ABC = x°, ∠BID = y° and ∠BOD = z° then  (z+x)/2y   =?

    Solutions

    ∠ABC=x, ∠BID=y, ∠BOD=z

    I is the incenter

    IB will be angle bisector

    ∠ABI= ½ ∠ABC= x/2

    O is circum center of ∆ABC

    ∠BAD= ½ ∠BOD = z/2

    Now in ∆ABI

    y=x/2+z/2=(x+z)/2y=1

     

  • Question 7/10
    1 / -0

    If the sides of each square is 20cm. find the area for shaded region?

    Solutions

     

  • Question 8/10
    1 / -0

    In the given figure, AO=CD where O is the center of the circle what is ∠ APB equal to?

    Solutions

    OC=OD=OA=CD=r

    ∆OCDis an equilateral triangle

    ∠OCD=∠ODC=∠COD=60

    & ∠ACB=90

    Now angles made by same arc CD

    ∠CBD = ½ x ∠COD = ½ x 60 = 30

    In PCB

    ∠APB = 180 – 90 – 30 = 60

     

  • Question 9/10
    1 / -0

    The elevation of the top of a tower from a point on the ground is 45°. On travelling 120 m from the point towards the base of tower, the elevation of the top becomes 60°. The height of the tower (in m) is :-

    Solutions

     

  • Question 10/10
    1 / -0

    Solutions

     

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