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IBPS Clerk 2020 Aptitude Test - 7
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IBPS Clerk 2020 Aptitude Test - 7

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  • Question 1/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    895, 623, 487, 419, 385, ?

    Solutions

    895               623                  487                  419                  385                  368

                272                  136                  68                    34                    17

                (÷2)                 (÷2)                 (÷2)                 (÷2)                 (÷2)

     

  • Question 2/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    15, 25.5, 46.5, 78, 120, ?

    Solutions

    15 + (1 * 10.5) = 25.5

    25.5 + (2 * 10.5) = 46.5

    46.5 + (3 * 10.5) = 78

    78 + (4 * 10.5) = 120

    120 + (5 * 10.5) = 172.5

     

  • Question 3/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    3, 6, 15, 42, 123, ?

    Solutions

    3 + 31 = 6

    6 + 32 = 15

    15 + 33 = 42

    42 + 34 = 123

    123 + 35 = 366

     

  • Question 4/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    69, 86, 105, 126, ?

    Solutions

     

  • Question 5/10
    1 / -0

    What value should come in the place of (?) in the following number series?

    50, 56, 68, 86, 110, ?

    Solutions

    50 + 6 = 56

    56 + 12 = 68

    68 + 18 = 86

    86 + 24 = 110

    110 + 30 = 140

     

  • Question 6/10
    1 / -0

    In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.

    I: 2x2 – 55x + 378 = 0

    II: 2y2 + 37y + 171 = 0

    Solutions

    From I

    2x2 – 55x + 378 = 0

    =>2x2 – 27x - 28x + 378 = 0

    => (x – 14) (2x – 27) = 0

    => x = 14, 27/2

    From II

    2y2 + 37y + 171 = 0

    =>2y2 + 18y + 19y + 171 = 0

    => (2y + 19) (y + 9) = 0

    => y = -9, -19/2

    Hence, x > y

     

  • Question 7/10
    1 / -0

    In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.

    I: x2 + 11x + 28 = 0

    II: 9y2 + 32y + 15 = 0

    Solutions

    From I

    x2 + 11x + 28 = 0

    =>x2+ 7x + 4x + 28 = 0

    => (x + 4) (x + 7) = 0

    => x = -4, -7

    From II

    9y2 + 32y + 15 = 0

    =>9y2 + 27y + 5y + 15 = 0

    => (9y + 5) (y + 3) = 0

    => y = -3, -5/9

    Hence, x < y

     

  • Question 8/10
    1 / -0

    In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.

    I: x2 - 6x - 7 = 0

    II: y2 - 19y + 84 = 0

    Solutions

    From I

    x2 - 6x - 7 = 0

    =>x2 - 7x + x - 7 = 0

    => (x – 7) (x + 1) = 0

    => x = -1, 7

    From II

    y2 - 19y + 84 = 0

    =>y2 – 12y - 7y + 84 = 0

    => (y – 12) (y – 7) = 0

    => y = 12, 7

    Hence, x ≤ y

     

  • Question 9/10
    1 / -0

    In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.

    I: x2 + 9x - 52 = 0

    II: y2 + 4y - 32 = 0

    Solutions

    From I

    x2 + 9x - 52 = 0

    =>x2+ 13x – 4x - 52 = 0

    => (x – 4) (x + 13) = 0

    => x = 4, -13

    From II

    y2 + 4y - 32 = 0

    => (y + 8) (y – 4) = 0

    => y = 4, -8

    Hence relationship between x and y cannot be determined

     

  • Question 10/10
    1 / -0

    In each of the following questions, two equations are given. You have to solve both the equations to find the relation between x and y.

    I: x2 – 841 = 0

    II: y3 – 29791 = 0

    Solutions

    From I

    x2 – 841 = 0

    => x2 = 841

    => x = ± 29

    From II

    y3 – 29791 = 0

    => y3 = 29791

    => y = 31

    Hence, x < y

     

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