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Aptitude Test - 100
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Aptitude Test - 100
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  • Question 1/10
    1 / -0

    Directions For Questions

    Directions (1 – 4): Read the given data carefully and answer the questions as follow.

    In the laptop sales centre has different types of laptop for sales. The sales data given January to April month of 2018 as below

    ...view full instructions


    If the HP laptop price for March month is 21,000, what is the income of HP laptops in March month (in lakhs)?

    Solutions

    Price of HP laptops = 21000

    Total laptops sold out in March month = 13

    Total income = 13×21000 = 273000 = 2.73

     

  • Question 2/10
    1 / -0

    Directions For Questions

    Directions (1 – 4): Read the given data carefully and answer the questions as follow.

    In the laptop sales centre has different types of laptop for sales. The sales data given January to April month of 2018 as below

    ...view full instructions


    What is the ratio of the sale of HCL and Lenova laptops in the month of January and March to that of HP and Acer in the month of February and April?

    Solutions

    Number of HCL laptops in January = 42

    Number of HCL laptops in March = 40

    Number of Lenova laptops in January = 30

    Number of Lenova laptops in March = 38

    Total sale of HCL and Lenova laptops in the month of January and March = 42 + 40 + 30 + 38 = 150

    Number of HP laptops in February = 26

    Number of HP laptops in April = 16

    Number of Acer laptops in February = 25

    Number of Acer laptops in April = 23

    Total sale of HCL and Lenova laptops in the month of January and March = 26 + 16 + 25 + 23 = 90

    HP and Acer in the month of February and April = 90

    Ratio = 150 : 90

    = 5 :3

     

  • Question 3/10
    1 / -0

    Directions For Questions

    Directions (1 – 4): Read the given data carefully and answer the questions as follow.

    In the laptop sales centre has different types of laptop for sales. The sales data given January to April month of 2018 as below

    ...view full instructions


    If the price of Acer laptops marked as 10% above the cost price, the total income of acer laptops is 4,75,200 in March find the cost price of an Acer laptop in the month of March?

    Solutions

    Total income of Acer laptops in March = 4,75,200

    Total laptops sold in March month = 36

    Selling price of each laptop = 4,75,200÷ 36 = 13200

    Marked price = 110% of cost price

    110% → 13200

    100 % → 12000

    In March month an Acer laptop cost price = 12000

     

  • Question 4/10
    1 / -0

    Directions For Questions

    Directions (1 – 4): Read the given data carefully and answer the questions as follow.

    In the laptop sales centre has different types of laptop for sales. The sales data given January to April month of 2018 as below

    ...view full instructions


    In May month, HCL laptop sale has increase 25% of total sale of January and February month, how many HCL laptops sold in May month?

    Solutions

    Number of HCL laptops sold in January = 42

    Number of HCL laptops sold in February = 38

    Total = 80

    125% of 80 = 100

    Sale of HCL laptops in May = 100

     

  • Question 5/10
    1 / -0

    On side of a parallelogram is 16 cm. Its distance from the opposite side is 12 cm. The area of the parallelogram is

    Solutions

    Area of parallelogram = Base × Height

    Base = 16

    Height = 12

    Area of parallelogram = 16 × 12 = 192 cm2

     

  • Question 6/10
    1 / -0

    The longest chord of a circle PR measures 10 cm. If a point Q is situated on the circumference of the circle such that PQ=8cm, find the length of QR.

    Solutions

    Longest chord of a circle is it’s diameter.

    PR is the diameter of the circle and Q is a point on the circle.

    So ∆PQR = 90(Angle in a semicircle is a right angle)

    So, PR2 = PQ2 + QR2

    100 = 64 + QR2

    QR = 6 cm

     

  • Question 7/10
    1 / -0

    If each of the exterior angles of a regular polygon measures 18°, find the number of sides of the polygon.

    Solutions

    Sum of exterior angles of a regular polygon = 360°

    Number of sides = Sum/Each angle

    = 360/18

    = 20

     

  • Question 8/10
    1 / -0

    Arrange the following fractions in ascending order.

    6/8 , 66/133, 7/12, 1/4

    Solutions

    ¼ = 0.25

    7/12 is slightly greater than 0.5

    66/133 is slightly less than 0.5

    6/8 = 0.75

     

  • Question 9/10
    1 / -0

    If 80% of 760 + 40% of 320= 50% of x, find the value of x

    Solutions

    608 + 128 = 0.5x

    0.5x = 736

    X = 1472

     

  • Question 10/10
    1 / -0

    3610 × 5 = x ×210×815, find the value of x

    Solutions

    410×910×5=x×210×910

    X= 210×5

    X=1024×5

    =5120

     

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