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The points A (1, 2), B (2, 5) and C (5, 6) are the vertices of
∴ AB2 = (2 − 1)2 + (5 − 2)2 = 10 ⇒ AB = √10
AC2 = (5 − 1)2 + (6 − 2)2 = 32 ⇒ AC = √32
BC2 = (5 − 2)2 + (6 − 5)2 = 10 ⇒ BC = √10
But AC2 ≠ AB2 + BC2 (∵ 32 ≠ 10 + 10)
Hence, it is not right angled.
If α = cos−1(3/5),β = tan−1(1/3), where 0 < α,β < π/2, then α – β is equal to:
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6th term in expansion of (2x2 − 1/3x2)10 is
Compute real values of x and y if
Order of a differential equation is defined as the order of the highest order derivative and the degree of a differential equation, when it is a polynomial equation in derivatives, is defined as the highest power (positive integral index) of the highest order derivative.
The highest order derivative present in the given differential equation is d2y/dx2, so its order is two. It is a polynomial equation in d2y/dx2 and dy/dx and the highest power raised to d2y/dx2 is one, so its degree is one.
If A = {x : x is a multiple of 3} and B = {x : x is a multiple of 5}, then A – B is {where, means complement of A}
Given, A is a symmetric matrix and B is a skew-symmetric matrix.
If the standard Deviation of a set of data is 8.5%, what is its variance?
We know,
Variance = (S.D)2
= (8.5)2 = 72.25
If Sn = nP + 1/2n(n − 1)Q where Sn denotes the sum of the first n terms of an A.P. then the common difference is
Short-trick:
Sn = n/2{2P + (n − 1)Q}-----------(1)
The standard formula of Sn = n/2 × {2a + (n − 1)d}, where a is the first term and d is the common difference.
By, comparing the equation (1), with the standard formula of Sn , we get d = Q.
The radius of a cylinder is increasing at the rate of 2 cm/sec and its altitude is decreasing at the rate of 3 cm/sec. the rate of change of volume when the radius is 3 cm and the altitude is 5 cm is
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