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In the following question, select the word which can not be formed using the letters of the given word. LACTOBACILLUS
E is not present in the word LACTOBACILLUS. Therefore, we can not form the word TABLET.
Directions For Questions
In the following question, some statements are followed by some conclusions. Assuming the given statements to be true, find which of the following conclusions follow the given statements and choose appropriate answer choice.
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Statements:
All bulbs are tubes.
All tubes are roses.
No rose is a fruit.
Conclusions:
I. All roses are tubes
II. All bulbs are roses
Conclusions: I. All roses are tubes - (False) - as all tubes are roses II. All bulbs are roses - (true) - it is clear from the above diagram.
All perks are fees.
Some wages are fees.
All comforts are wages.
Conclusion:
I. Some comforts are not perks.
II. All comforts are perks.
III. All perks are wages.
IV. Some fees are comforts.
In a certain code, 253 means 'books are old', 546 means 'mom is old' and 378 means 'buy good books'. What stands for “are” in that code?
Hence, ‘are’ is coded as 2.
In a certain code language ‘how many goals scored’ is written as ‘5 3 9 7’, ‘many more matches’ is written as ‘9 8 2’ and ‘he scored five’ is written as ‘1 6 3’. How is ‘goals’ written in that code language?
how many goals scored = 5 3 9 7 …(i) Many more matches = 9 8 2 …(ii) he scored five = 163 …(iii) From (i) and (ii), many = 9 …(iv) From (i) and (iii), scored = 3 …(v) Using (iv) and (v) in (i), we get goals = 5 or 7
In the following question, select the missing number from the given alternatives.
1st Column:
(17+22)*2 =39*2=78
2nd Column:
(12+24)*2 =36*2=72
Similarly,
3rd Column:
(21+11)*2 =32*2=64
1st Column: (92-52)+4=(81-25)+4=56+4=60 2nd Column: (72-42)+4=(49-16)+4=33+4=37 Similarly, 3rd Column: (112-82)+4=(121-64)+4=57+4=61
The series will be, Second number – 4 × 4 ÷ 1 = 16 Third number – 16 × 5 ÷ 2 = 40 Fourth number – 40 × 6 ÷ 3 = 80 Fifth number – 80 × 7 ÷ 4 = 140 Six number – 140 × 8 ÷ 5 = ? ? = 28 × 8 ? = 224
In every column, we get the fourth number by multiplying first and second element and then dividing the results by third element. 1st
The average weight of A, B and C is 50 kg. If the average weight of A and B be 45 kg and that of B and C be 48 kg, then the weight of B is:
Let A, B, C represent their respective weights. Then, we have,
A + B + C = (50 x 3) = 150 ___(1)
A + B = (45 x 2) = 90 ________(2)
B + C = (48 x 2) = 96 _________(3)
Adding (2) and (3), we get: A + 2B + C = 186 _________(4)
Subtracting (1) from (4), we get , B = 186-150=36
B's weight = 36 kg.
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