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The angle of depression of a point from the top of a 200 m high tower is 45 °. The distance of the point from the tower is
Thus, the distance of the point from the tower = 200 m Hence, option B is correct.
Evaluate: 3 cos 80 ° cosec 10 °+ 2 cos 59 ° cosec 31 °
3 cos 80 º.cosec 10 º + 2 cos 59 º.cosec 31 º
= 3 cos(90 º – 10 º).cosec 10 º + 2 cos(90 º – 31 º).cosec 31 º
= 3 sin 10 º.cosec 10 º + 2 sin 31 º.cosec 31 º
= 3 + 2 = 5
2 cosec2 23 ° cot2 67 ° − sin2 23 ° − sin2 67 ° − cot267 ° is equal to
If cos67o.cosecθ = 1 then value of θ is
Cos67ocosecθ=1
cos(90-23)cosecθ = 1
sin23cosecθ =1
θ = 23o
Two men are on opposite sides of a tower. They measure the angles of elevation of the top of the tower as 30o and 45o, respectively. If the height of the tower is 50 m, find the distance between the two men. (Take √3 = 1.73)
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