Solutions
Given that in the set of real numbers R,
aRb if f a - b + √2 is an irrational number
Reflexive : Reflexive relation on a set is a binary element in which every element is related to itself.
x - x + √2 = √2(irrational) for every x
So R is a reflexive relation.
Symmetric : Let a= √2
, b = 1 so a- b + √2 = √2 - 1 + √2 = 2√2 - 1 which is an irrational number
For symmetric relation: (a,b) ∈R which implies that (b,a) ∈R
So if (√2,1) ∈R then (1,√2) should also belong to R
⇒ a= 1 , b=√2
⇒ a - b + √2 = 1 - √2 + √2 = 1 which is not an irrational number
⇒ (1,√2) does not belong to R
So R is not symmetric relation.