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A father is 30 years elder than his son. After 10 years, the ratio of their ages will be 5:2. Find the sum of their present ages.
Let father’s age be x Son’s age = x-30 Given that 2(x+10) = 5(x-20) => 5x -2x = 120 => 3x = 120 => x = 40 So father’s present age is 40. Hence the age of the son would be 10 So required sum = 40+10 = 50 years
Find the area of the trapezium if its parallel sides are of length 13cm and 7 cm respectively and the distance between the parallel sides is 5cm?
Let the parallel sides be of length 13cm and 7cm. Area = 1/2(13 + 7)(5) = 50
X and Y partnered and started a business by investing in the ratio 3:5 respectively. After few months Y left the business. At the end of the year the profits were distributed among X and Y in the ratio 9:10. After how many months did Y leave the business?
The profits between X and Y will be distributed in the ratio of their weighted investments. Weighted investment = (Investment amount) xx (Time period of investment) Weighted investment of X = 3*12 = 36 Weighted investment of Y = 5*x = 5x It is given that the ratio of profits is 9:10 So we get,
Thus Y left the business after 88 months.
Ekraj lent a certain amount 10% p.a simple interest for 3 years. He realizes that had he lent the amount for compound interest, he could have earned Rs. 9300 more. The amount lent by Ekraj is
It has been given that the difference between the interest earned through simple and compound interest after 3 years is Rs. 9300.
The average weight of all the 24 students in a class is 48 kg. If the weights of two more students who weigh 60 kg each and the weight of a teacher are considered, the average becomes 50kg. Find the weight of the teacher.
Sum of the weights of all the students in the class = 24*48 = 1152 New sum after addition of students and teacher = 1152 + 2*60 + w(weight of the teacher) = 1272 + w ==> 1272 + w = 27 * 50 = 1350 ==> w = 78 kg
Directions For Questions
Read the information given below carefully and answer the questions which follow. The following table gives the data of the number of candidates appearing for BAT Exam every year. On the basis of the data given in the table, answer the question
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The number of candidates appearing in the examination in 2015 increased by 8% from 2011 to 2015. If only 25% of the candidates were able to qualify the examination, find the number of candidates qualified the examination in 2015?
Increased number of candidates from 2011 => 8% of 87500 = 7000 Number of candidates appeared in 2015 => 87500 + 7000 = 94500 Number of candidates qualified in 2015 => 25% of 94500 = 23625 => Option E
If the number of male candidates who qualified in 2012 was 6500, find the ratio of number of qualified female candidates to the number of qualified male candidates?
Number of qualified candidates => 28% of 75000 = 21000 Number of qualified female candidates => 21000 - 6500 = 14500 Ratio of Female to Male qualified candidates => 14500 : 6500 => 29:13 => Option A
If the average number of qualified candidates in 2011 and 2014 is 37125. Find the percentage of candidates qualified in 2011?
Number of qualified candidates in 2014 => 40% of 120000 = 48000 Let the number of qualified candidates in 2011 be ‘x’ => x + 48000 = ( 2 x 37125 ) => x = 26250 Percentage of qualified candidates =>
If the difference between the qualified male candidates and the qualified female candidates in 2013 was 13650. Find the number of appeared candidate in 2013?
Let number of qualified candidates be 13k => Male qualified = 5k and Female qualified = 8k => 3k = 13650 => k = 4550 => 13k = 59150 Let number of appeared candidates be ‘y’ => 65% of y = 59150 => y = 91000
If during 2010, the ratio of the candidates who appeared to the candidates who qualified the exam was 5:2. What percent of qualified female candidates constitute to the appeared candidates?
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