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RRB NTPC Aptitude Test - 41
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RRB NTPC Aptitude Test - 41
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  • Question 1/10
    1 / -0

    Rita invested a total of Rs. 13,200 in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3347.52, what was the amount invested in Scheme B?

    Solutions

    14 × 2 × P/100 + 11 × 2× (13200 – P)/100 = 3347.52

    (28 – 22)P = 334752 – 290400

    6P = 44352

    P = 7392

    So Amount invested in B = 13200 – 7392 = 5808

     

  • Question 2/10
    1 / -0

    Five years ago, the average age of Husband and Wife was 25. A son was born and the average age Family today is 21. What will be the age of son after five years?

    Solutions

    Total age of Husband + Wife Today = 25 × 2 + 5 × 2 = 50 +10 =60

    Total age of family = 21 × 3 = 63

    Age of son at present = 63 – 60 = 3

    After 5 year age of son = 5+ 3 = 8

     

  • Question 3/10
    1 / -0

    If O is the centroid of the equilateral triangle PQR of perimeter 36 cm. Then find the length of OP?

    Solutions

     

  • Question 4/10
    1 / -0

    If the cost price of 50 Balloons is equal to the selling price of 40 Balloons, then find the profit or loss percentage?

    Solutions

    50 CP = 40SP

    CP/SP = 4/5

    CP < SP

    % Profit = (5 – 4)/4 × 100 = 25 %

     

  • Question 5/10
    1 / -0

    Find the unit place of the following

    27 × 13 – 258 × 31

    Solutions

    Unit place in 27 × 13 = 1

    Unit place in 258 × 31 = 8

    Unit place       27 × 13 – 258 × 31

    = 11– 8 =3

     

  • Question 6/10
    1 / -0

    A boat can cover a distance of 2 km upstream in 20 minutes and downstream in 8 minutes. What is the speed of the stream?  

    Solutions

    Upstream speed = 2 /1/3 = 6 km/hr

    Downstream speed = 2/8 × 60 = 15km/hr

    So speed of stream = (15 – 6)/2 = 9/2 = 4.5 km/hr

     

  • Question 7/10
    1 / -0

    The difference between CI and SI for 3 years is 899. If the rate of interest is 10% then find the Principal?

    Solutions

    Difference= P(r/100)2 × [(r+300)/100]

    899 = P (10/100) 2 [310/100]

    899 x 100 x 100 =P × 310

    899000/31 = P

    P = 29000

     

  • Question 8/10
    1 / -0

    Directions For Questions

    In the following graph number of students come in library from Monday to Friday is given. Read the graph carefully and answer the question

    Number of Student Visit Library

    ...view full instructions


    What is the ratio of student visited library on Tuesday to that who visited on Thursday?

    Solutions

    Required Ratio = 215/480 = 43 : 96

     

  • Question 9/10
    1 / -0

    Directions For Questions

    In the following graph number of students come in library from Monday to Friday is given. Read the graph carefully and answer the question

    Number of Student Visit Library

    ...view full instructions


    Find the average of students who visited the library on Monday, Wednesday and Friday?

    Solutions

    Require Average = (295 + 400 + 418)/3 = 1113/3 = 371

     

  • Question 10/10
    1 / -0

    Directions For Questions

    In the following graph number of students come in library from Monday to Friday is given. Read the graph carefully and answer the question

    Number of Student Visit Library

    ...view full instructions


    Students who visited library on Friday are how much percent more than the student who visited on Wednesday?

    Solutions

     (418 – 400)/400 x 100 =18/4 = 4 1/2 %

     

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