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RRB NTPC Aptitude Test - 40
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RRB NTPC Aptitude Test - 40
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  • Question 1/10
    1 / -0

    Find the factors of following   (4x2 – x– 3)

    Solutions

    4x2 – x– 3

    =4x2 – (4 – 3) (x– 3)

    = 4x(x – 1) +3 (x – 1)

    =(x – 1)(4x + 3)

     

  • Question 2/10
    1 / -0

    Find the mode and median of the data 7, 6, 8, 6 ,8 , 7 , 8 , 6 , 8

    Solutions

    Median = 6, 6, 6, 7, 7, 8, 8, 8, 8

    Median is the term which come in middle after arranging series in ascending order so here 7.

    Mode is the term whose frequency is more so 8. 

     

  • Question 3/10
    1 / -0

    Find the length of diagonal of rectangle if the perimeter is 34 cm and breadth is 5 cm?

    Solutions

    2(l + b) = 34

    l + b = 17

    l = 17 – 5 = 12

    So diagonal is = √ (5)2 + (12)2  = √25 + 144

    = √169 = 13

     

  • Question 4/10
    1 / -0

    If 32 cotA = 24 then find the value of (sinA + CosA)/(sinA –cosA) =?

    Solutions

    cotA = 24/32

    cosA/sinA = 3/4

    (sinA + CosA)/(sinA –cosA) = (4+3)/(4-3) =7

     

  • Question 5/10
    1 / -0

    A shopkeeper purchased 10 boxes of pen. In each box there are 10 pens.  Each pen cost Rs. 8.If he sold each pen at 12 % profit. What is the total selling price?

    Solutions

    Total Number of pen = 10 x 10 =100

    Cost Price of 100 pen = 8 x 100 =800

    Selling price = 800 x 112/100 = 896

     

  • Question 6/10
    1 / -0

    Simplify the following?

    Solutions

     

  • Question 7/10
    1 / -0

    If the sum of digit is 9 and difference between the digit at ten’s place and unit place is 1 find the two digit number?

    Solutions

    Unit digit = x

    Ten’s digit = x+1

    x+ x+1  = 9

    2x=8 => x=4

    So Number= 10(x + 1) + x = 50 + 4 = 54

     

  • Question 8/10
    1 / -0

    Simplify the following   2.55+ 22.5 + 2222.555+ 222.5555=?

    Solutions

    2.55+ 22.5 + 2222.555+ 222.5555

    = (2+22+2222+222) + (0.5 + 0.55 + 0.555+ 0.5555)

    = 2468 + 2.1605

    = 2470.1605

     

  • Question 9/10
    1 / -0

    If the value of A =45◦ then value of sin 2A + cos2A = ?

    Solutions

    sin 2A + cos2A = sin 245+ cos245

    = 1/2 + 1/2 =1

     

  • Question 10/10
    1 / -0

    A starts business with Rs.6500 and after 8 months, B joins with A as his partner. After a year, the profit divided in the 3 : 5. What is B's contribution in the capital?

    Solutions

    Lets assume B’s Capital = B

    6500 × 12 /4 × B = 3/5

    B = 6500 × 5 = 32500

     

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