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IBPS PO 2019 Aptitude Test - 5
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IBPS PO 2019 Aptitude Test - 5
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  • Question 1/10
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    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    Quantity I: Ram invested Rs.3500 at simple interest rate of 12% per annum for 8 years and also he invested Rs.4200 at simple interest rate 18% per annum for 5 years. At the end of 8 years ram received the total amount is?

    Quantity II: Ram had Rs.28000. A part of which he lent to his sister at rate of 12% interest per annum and the other part is lent to his friend at 15%. At the end of year, Ram received the total interest of Rs.3900. What the amount of money lent by him to his sister?

    Solutions

    From quantity I,

    SI=3500+3500*12*(8/100) =Rs.6860

    SI=4200+4200*18*(5/100) =Rs.7980

    Total amount=6860+7980=Rs 14840

    From quantity II,

    x *12*1/100+ (28000-x)*15*1/100=3900

    12x+28000*15-15x=390000

    3x=30000

    x=Rs 10000

     

  • Question 2/10
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    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    A, B and C started the business with the investment of Rs.12000, Rs.10000 and Rs.16000 respectively. After 4 months D joins them with investment of Rs.17000 and C withdrew Rs.4000. After 6 more months A withdrew Rs.3000, B withdrew Rs.2000 and C withdrew Rs.3000 respectively. At the end of one year the total profit is Rs.27200.

    Quantity I: Profit share of A

    Quantity II: Profit share of D

    Solutions

    Ratio of the Profit share A, B, C and D= (12000*10+9000*2):(10000*10+8000*2):(16000*4+12000*6+9000*2):(17000*8)

    =69:58:77:68

    From quantity I,

    A’s share= (69/272)*27200=Rs 6900

    From quantity II,

    D’s share= (68/272)*27200=Rs 6800

     

  • Question 3/10
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    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    Quantity I: The length of the rectangle is four times of the breadth of the rectangle. The volume of the cuboid is equal to the area of the rectangle. The ratio of the height, breadth and length of the cuboid is 1:2:2. The difference between the height and breadth of the cuboid is 4cm. Find the length of the rectangle.

    Quantity II: 32 cm

    Solutions

    From quantity I,

    Length of rectangle =4*breadth of rectangle

    Since, the difference between the height and breadth of the cuboid is 4cm,

     Height of the cuboid= (1/1)*4=4 cm

    Breadth of the cuboid= (2/1)*4=8 cm

    Length of the cuboid= (2/1)*4=8 cm

    Then, Volume of the cuboid=8*8*4=256 cm3

    (i.e) 4b*b=256

    Then, Breadth of the rectangle=8cm

    Length of the rectangle =8*4=32cm

     

  • Question 4/10
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    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    Quantity I: Anu’s present age is three times of Banu’s present age and three-fifth of Divya’s present age. The sum of the present ages of Anu, Banu and Divya is 72 years. What is the difference between Banu’s present age and Divya’s present age?

    Quantity II: A’s present age is 1.5 times of the age of B. After 10 years, the ratio of the ages of A and B is 4:3. What is the present age of A?

    Solutions

    From quantity I,

    A=3B

    A= (3/5)*D

    A+A/3+5A/3=72

    9A=72*3

    A=24 years

    Then, present age of Banu=24/3=8 years

    And, present age of Divya=5(24)/3=40 years.

    Required Difference =40-8=32 years

    From quantity II,

    A=1.5B

    A= (3/2)*B

    (A+10) / ((2A/3) +10) =4/3

    3A+30= (8A/3)+40

    9A+90=8A+120

    A=30 years

     

  • Question 5/10
    1 / -0

    Each question contains a statement followed by Quantity I and Quantity II. Read the contents clearly and answer your questions accordingly.

    Quantity I: The average weight of 21 boys is 64kg. If the weight of teacher is added, then the average is increased by 1 kg. What is the weight of teacher?

    Quantity II: What will be the compound interest accrued on the sum of Rs.500 at the rate of 8% per annum in 2 years?

    Solutions

    From quantity I,

    Total weight of the boys=21*64=1344kg

    Total weight of boys and teacher=22*65=1430

    Weight of teacher=1430-1344=86kg

    From quantity II,

    CI = [500*(1+8/100)2]-500

        =500*104/625

        =Rs.83.2

     

  • Question 6/10
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    Directions For Questions

    Read the following information carefully and answer the given questions:

    Statement I: Box A contains 6 green balls, 4 yellow balls, 5 White balls and 5 Red balls.

    Statement II: Box B contains 8 Red balls, 5 White balls, 4 Green balls and 3 Yellow balls.

    Statement III: Box C contains 3 White balls, 2 Red balls, 4 Green balls and 5 Yellow balls.

    Statement IV: Box D contains 2 Yellow balls, 6 Green balls, 4 Red balls and 3 White balls.

    Statement V: Box E contains 4 White balls, 2 Green balls, 6 Red balls and 3 Yellow balls.

    ...view full instructions


    If 4 balls are picked from Box A and Box B each, then what is the difference between the probability of getting all four yellow balls from box A and the probability of getting all four Red balls from Box B?

    Solutions

    Probability of getting 4 yellow balls from box A=4C4/20C4

    =1/20C4

    Probability of getting 4 red balls from box B=8C4/20C4

    =70/20C4

    Required Difference=69/20C4=23/1615

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    Statement I: Box A contains 6 green balls, 4 yellow balls, 5 White balls and 5 Red balls.

    Statement II: Box B contains 8 Red balls, 5 White balls, 4 Green balls and 3 Yellow balls.

    Statement III: Box C contains 3 White balls, 2 Red balls, 4 Green balls and 5 Yellow balls.

    Statement IV: Box D contains 2 Yellow balls, 6 Green balls, 4 Red balls and 3 White balls.

    Statement V: Box E contains 4 White balls, 2 Green balls, 6 Red balls and 3 Yellow balls.

    ...view full instructions


    Three-fifth of White balls from Box A, one-fourth of the red balls from box B, 75% of the green balls from box C, 50% of the Yellow balls from box D and half of the Red balls from box E are collected and kept in a new box F. What is the probability of getting three Red balls from the new box F?

    Solutions

    Number of White balls from box A= (3/5)*5=3

    Number of Red balls from box B= (1/4)*8=2

    Number of Green balls from box C= (75/100)*4=3

    Number of Yellow balls from box D= (50/100)*2=1

    Number of Red balls from box E= (1/2)*6=3

    Total number of balls in box F=3+2+3+1+3=12

    Total number of Red balls=2+3=5

    Then, Required probability=5C3/12C3=1/22

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    Statement I: Box A contains 6 green balls, 4 yellow balls, 5 White balls and 5 Red balls.

    Statement II: Box B contains 8 Red balls, 5 White balls, 4 Green balls and 3 Yellow balls.

    Statement III: Box C contains 3 White balls, 2 Red balls, 4 Green balls and 5 Yellow balls.

    Statement IV: Box D contains 2 Yellow balls, 6 Green balls, 4 Red balls and 3 White balls.

    Statement V: Box E contains 4 White balls, 2 Green balls, 6 Red balls and 3 Yellow balls.

    ...view full instructions


    Four green balls picked from box D is what percent of the three green balls picked from box C?

    Solutions

    Green balls from box D=6C4/15C4=1/91

    Green balls from box C=4C3/14C3=1/91

    Required percentage= (1/91)/(1/91)*100=100%

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    Statement I: Box A contains 6 green balls, 4 yellow balls, 5 White balls and 5 Red balls.

    Statement II: Box B contains 8 Red balls, 5 White balls, 4 Green balls and 3 Yellow balls.

    Statement III: Box C contains 3 White balls, 2 Red balls, 4 Green balls and 5 Yellow balls.

    Statement IV: Box D contains 2 Yellow balls, 6 Green balls, 4 Red balls and 3 White balls.

    Statement V: Box E contains 4 White balls, 2 Green balls, 6 Red balls and 3 Yellow balls.

    ...view full instructions


    If all the balls from box A and Box E are mixed, then what is the probability of getting 5 yellow balls?

    Solutions

    Total Number of balls in box A=20

    Number of Yellow balls in box A=4

    Total Number of balls in box E=15

    Number of Yellow ball in box E=3

    Required probability=7C/35C5=3/46376

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the given questions:

    Statement I: Box A contains 6 green balls, 4 yellow balls, 5 White balls and 5 Red balls.

    Statement II: Box B contains 8 Red balls, 5 White balls, 4 Green balls and 3 Yellow balls.

    Statement III: Box C contains 3 White balls, 2 Red balls, 4 Green balls and 5 Yellow balls.

    Statement IV: Box D contains 2 Yellow balls, 6 Green balls, 4 Red balls and 3 White balls.

    Statement V: Box E contains 4 White balls, 2 Green balls, 6 Red balls and 3 Yellow balls.

    ...view full instructions


    All the balls from all the 5 boxes are mixed and 5 balls are picked. What is the difference of the probability of getting 5 White balls and the probability of getting 5 Red balls?

    Solutions

    Total Number of balls=20+20+15+14+15=84

    Total Number of red balls=25

    Total Number of white balls=20

    Required Difference=25C5/84C5-20C5/84C5=6271/5145336

     

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