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SBI Clerk 2019 Aptitude Test - 14
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SBI Clerk 2019 Aptitude Test - 14

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  • Question 1/10
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    Directions For Questions

    In the following questions two equations I and II are given. You have to solve both the equations and give answer:

    a) If x ≥ y

    b) If x > y

    c) If x ≤ y

    d) If x < y

    e) If x = y (or) no relation can be established between x and y

    ...view full instructions

    I. x^2 + 6 x + 8 = 0

    II. y ^2+7 y + 12 = 0

    Solutions

    I.x2 + 6x + 8 = 0

    =>x2 + 2x + 4x + 8 = 0

    =>x(x + 2) + 4(x + 2) = 0

    =>(x + 4)(x + 2) =0

    => x= -4 or -2

    II.y2 + 7y + 12 = 0

    =>y2 + 4y + 3y + 12 = 0

    =>y(y + 4) + 3 (y + 4) = 0

    =>(y + 3) (y + 4) = 0

    => y = – 3 or – 4

     

  • Question 2/10
    1 / -0

    Directions For Questions

    In the following questions two equations I and II are given. You have to solve both the equations and give answer:

    a) If x ≥ y

    b) If x > y

    c) If x ≤ y

    d) If x < y

    e) If x = y (or) no relation can be established between x and y

    ...view full instructions

    I. x^2 + 20 = 9x

    II. y^2 + 42 = 13y

    Solutions

    I.x2 – 9x + 20 = 0

    x2 – 5x – 4x + 20 = 0

    x(x – 5) – 4 (x – 5) = 0

    (x – 4) (x – 5) = 0

    x = 4 or 5

    II.y2 – 13 y + 42 = 0

    =>y2 – 7y – 6y + 42 = 0

    =>y(y – 7) – 6(y – 7) = 0

    =>(y – 6) (y – 7) = 0

    => y = 6 or 7

     

  • Question 3/10
    1 / -0

    Directions For Questions

    In the following questions two equations I and II are given. You have to solve both the equations and give answer:

    a) If x ≥ y

    b) If x > y

    c) If x ≤ y

    d) If x < y

    e) If x = y (or) no relation can be established between x and y

    ...view full instructions

    I. 2x + 3y = 14

    II. 4x + 2y = 16

    Solutions

    2x + 3y = 14….(i)

    4x + 2y = 16….(ii)

    On solving, (i) x 2 – (ii) we get,

    4x + 6y – 4x – 2y = 28 – 16

    => 4y = 12 =>y = 3

    So, the value of x will be –

    2x + 3 x 3 = 14

    =>2x = 14 – 9 = 5 => x = 5/2

     

  • Question 4/10
    1 / -0

    Directions For Questions

    In the following questions two equations I and II are given. You have to solve both the equations and give answer:

    a) If x ≥ y

    b) If x > y

    c) If x ≤ y

    d) If x < y

    e) If x = y (or) no relation can be established between x and y

    ...view full instructions

    I. x = √961

    II. y = √1089

    Solutions

    I. x = √961 = 31

    II. y = √1089 = 33

     

  • Question 5/10
    1 / -0

    Directions For Questions

    In the following questions two equations I and II are given. You have to solve both the equations and give answer:

    a) If x ≥ y

    b) If x > y

    c) If x ≤ y

    d) If x < y

    e) If x = y (or) no relation can be established between x and y

    ...view full instructions

    I. x^2 – 19x + 84 = 0

    II. y^2 – 25y + 156 = 0

    Solutions

    I.x2 – 19 x + 84 = 0

    => x2 – 12 x – 7 x + 84 = 0

    => x(x – 12) – 7 (x – 12) = 0

    => (x – 7) (x – 12) = 0

    So, x = 7 or x = 12

    II.y2 – 25 y + 156 = 0

    => y2 – 12 y – 13 y + 156 = 0

    => y(y – 12) – 13 (y – 12) = 0

    => (y – 13) (y – 12) = 0

    So, y = 12 or 13

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Refer to the table and answer the given questions.

    ...view full instructions

    If the number of male post graduate employees in company H is 1800, what percent of the female employees in that particular company are post graduate?

    Solutions

    Number of Post graduate employees in Company H = 3360 *(80/100) = 2688
    Number of female post graduate employees in Company H = 2688 – 1800 = 888
    Required Percentage = (888 * 100)/1200 = 74%

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Refer to the table and answer the given questions.

    ...view full instructions

    In which of the given companies is the percentage of women employees with respect to the total number of employees (both males and females) in that company the second lowest?

    Solutions

    Company A : (7/12 )*100 = 58.33%
    Company B : (5/16 )*100 = 31.25%
    Company C : (11/21)*100 = 52.38%
    Company D : (2/5)*100 = 40%
    Company E : (6/13)*100 = 46.15%
    Company F : (21/41)*100 = 51.21%
    Company G : (7/15)*100 = 46.66%
    Company H : (5/14)*100 = 35.71%

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Refer to the table and answer the given questions.

    ...view full instructions

    What is the ratio of the total number of male employees in companies B and H together to the total number of female employees in Companies C and D together?

    Solutions

    = [2880 * (11/16)/ 2310 * (11/21) + 3360 * (9/14)/ 3575 * (2/5)] = (1980 + 2160)/(1210 + 1430) = 414/264 = 69:44

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Refer to the table and answer the given questions.

    ...view full instructions

    What is the difference between the average number of post graduate employees in companies A, B and D together and the average number of post graduate employees in companies F, G and H?

    Solutions

    Average number of post graduate employees in companies A, B and D = (1926 + 1872 + 2145)/3 = 5943/3 = 1981
    Average number of post graduate employees in companies F, G and H = (2091 + 2046 + 2688)/3 = 6875/3 = 2275
    Difference = 2275 – 1981 = 294

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Refer to the table and answer the given questions.

    ...view full instructions

    Which of the given companies has the highest number of average employees per office?

    Solutions

    Company A – 2568/16 = 160.5 ; Company B – 2880/18 = 160
    Company C – 2310/14 = 165 ; Company D – 3575/22 = 162.5
    Company E – 2054/13 = 158 ; Company F – 2788/17 = 164
    Company G – 3720/24 = 155 ; Company H – 3360/21 = 160

     

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