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The ratio of the ages of Arun and Bijoy is 7 : 4. The sum of their ages is 55.After 4 years what will be their ratio.
Sum of ages is 55.
Let their ages be 7x and 4x.
Then 11x = 55
And x = 5
Then ages are 35 and 20. After 4 years their ages will be 39 and 24. They will bear a ratio of 13 : 8
By selling 100 chocolates for Rs 169, a chocolate trader loses 35%. How many chocolates should he sell for Rs 97.5 to make a profit of 25%?
Selling price of 1 chocolate = Rs 169/100
CP of 1 chocolate = 169/100 ×100/65 = Rs 13/5 = Rs 2.6
Now if he sell some amount of chocolates for Rs 97.5 , he gains 25%, then in that case CP of that amount of chocolates will be= 97.5/125 ×100 = Rs 78
But we know Cp of each chocolate is Rs 2.6
So number of chocolates = 78/2.6 = 30
Ramu want to buy the following items in the following price range cheese between Rs 65 to Rs 70 per kg, Khoya in the price range of Rs 80 to Rs 90 per kg and Milk packets at Rs 18 per litre. Following Omfeds are near her and they have the following prices of the products, from which omfed should Ramu buy?
1. Omfed A sells cheese at Rs 34 per half kg, khoya at Rs 46 per half kg and milk at Rs 18 per litre.
2. Omfed B sells cheese at Rs 35 per half kg, 2 litre milk at Rs 38 and khoya at Rs 21 per quarter kg.
3. Omfed C sells cheese at Rs 33 per half kg, khoya at Rs 21 per quarter kg, milk at Rs 18 per litre.
4. Omfed C sells cheese at Rs 72 per kg, khoya at Rs 89 per kg and milk at Rs 18 per litre.
Looking at all these conditions, Omfed A and Omfed B fail the condition by the price of Cheese and Milk respectively. Comparing Omfed C and D, Omfed C is satisfied all the conditions.
Shagun changes the marked price of an item to 60% above its cost price. What percentage of discount can be allowed to gain 20%.
Let the CP be Rs 100,
Then MRP would be 160.
To gain 20%, the Sp should be 120.
Discount = MP – SP = 160 – 120 = RS 40
Discount % = Discount/MP ×100
= 40/160 ×100 = 25%.
A work can be done by 60 workers in 50 days. They start the work together but 4 workers dropout every 10 days. In how many days would the work be completed now?
Total work = 60×50= 3000 units
First 10 days = 10× 60 = 600
Second next 10 days=10× 56 = 560
Third next 10 days = 10× 52 = 520
Fourth next 10 days = 10× 48 = 480
Fifth next 10 days= 10× 44 = 440
Total work in 50 days = 2600
Left out work = 400 units.
Now for the next 10 days, there are 40 workers, they will complete the work in
400/40 = 10 days.
Total days required = 50 +10 = 60days.
If A can do a piece of work in 15 days, B can do it in 45 days, C can do it in 60 days. If first day of work starts with A and B, second day of work done by B and C and third day of work done by C and A, this way of work is continue till the work is completed. By the way how many days the work will complete?
A = 15 days
B = 45 days
C = 60 days
LCM of 15, 45, 60 = 180
So, A can do 12 units per day
B = 4 units/day
C = 3 units/day
First day work done by A + B = 16 units
Second day work done by B + C = 7 units
Third day work done by C + A = 15 units
Total work done is first 3 days = 16 + 7 + 15 = 38 units
Work done in 12 days = 38 × 4 = 152 units
Remaining work = 180 – 152 = 28 unit done by
13th day → A + B = 16 units
Remaining Work = 12 units
14th day → B + C = 7 units
Remaining work = 5 units
15th day work done by C + A = 5/15 = 1/3 days
So the total work completed in 12 + 1 + 1 + 1/3 days = 14 1/3 days
A train crosses a pole in 15 mins and a platform in 20 minutes. What is the length of train is platforms length is 500 m?
Let the train length be x, is speed is constant then distance directly proportional to time
x/(x+500) = 15/20 = 3/4
4x = 3x+1500
x = 1500m
If a person increases his speed by 20%, he reaches his destination 20 minutes earlier. What is the time he usually takes?
(Increased speed)/(Earlier speed ) = 120% of x = 6x/5
Since the distance is constant, hence time is inversely proportional to speed
(New time)/ (Earlier time) = 5/6
A difference of 1 unit in ratio refers to 20 minutes, and then 6 units will refer to
6 × 20 = 120 min = 2 hrs
If the compound interest on a sum for 2 years at 12 1/2 % p. a is Rs 510, the simple interest on the same sum at the same rate for the same period of time is
Now compound interest for 2 years at 12.5 % will amount to net
x+ x + x2/100
12.5 + 12.5 + 12.52/100
= 25 + 1.5625
= 26.5625
Now simple interest in two years = 12.5 + 12.5 = 25%
Simple interest = 510/26.5625×25 = 480
If a sum of Rs 2340 were to be distributed among A, B and C in the ratio of 2 : 3: 4, instead of 1/2, 1/3, 1/4, who was benefitted most and by how much?
Actual ratio
A : B : C → 1/2 : 1/3 : 1/4 = (6 : 4 : 3)/12
A : B : C = 6 : 4 : 3
Rs. 2340 is distributed as
A = (2340 × 6) /13 = 180 × 6 = 1080
B = (2340 × 4)/13 = 180 × 4 = 720
C = (2340 × 3) /13 = 180 × 3 = 540
But the ratio by mistakenly taken as
A : B : C = 2 : 3 : 4
By the way the distribution is
A = (2340×6) / 9 = 260 × 2 = 520
B = (2340 × 4) / 9 = 260 × 3 = 780
C = (2340 × 3) / 9 = 260 × 4 = 1040
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