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Direction: What value should come in place of question mark (?) in the following question?
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20% of 40 + ? % of 80 = 120
20% of 40 + ? % of 80 = 120 8 + ?% of 80 = 120 ?% of 80 = 120 –8 = 112
? = 112 × 100 / 80
= 140
(33)2–2967 ÷ 43 =? ×17
1089 – 69 = ? ×17
1020 = ? × 17
? = 1020/17
? = 60
Direction: What should come at the place of question mark (?) in the following question?
Directions: What value should come in place of question mark (?) in the following question.
18.5×3+7.2-16.5=(?)+22.7
Substituting (?) with “x”
55.5+7.2-16.5=x+22.7
46.2=x+22.7
46.2-22.7=x
x=23.5
Direction:What value should come in place of the question mark (?) in the following question?
The average age of P and Q is 35 years. If R replaces P, the average age is 31 years, if R replaces Q average age is 36 years. If the average age of S and T is half of average age of P, Q and R. then average age of all the five people is
let the age of P, Q, R, S, and T
P + Q = 35 * 2 =70 ……..(1)
R + Q = 31 * 2 =62 ……………….(2)
P + R = 36 * 2 = 72 …………(3)
From (1) (2) and (3)
P+Q+R= 204/2= 102
Average age of P and Q =1/2 * [( X + Y + Z)/3]
= 102/6 = 17
Sum of the age of P and Q = 34
Average age of all the five people = (34 + 102)/5 = 27.2 years
Direction: Read the following questions and answer accordingly.
Vijay rows 3 km per hour in still water. if the river is running at 1 km per hour, it takes him 45 minutes to row to a place and back. How far is the place?
Suppose distance is x km
Speed in downstream = (3 + 1) km/hr = 4 km/hr
Speed in upstream = (3 - 1) km/hr = 2 km/hr
According to question,
Time-taken by vijay for downstream + time- taken for upstream =
x/4 + x/2 = 45/60
x=1km
A sum becomes Rs.24200 in 2 years and Rs.29282 in 4 years at compound interest, compounded annually. Find the rate of interest.
Let the principal be p.
24200=p (1+(r/100)) 2
29282=p (1+(r/100)) 4
Dividing the second equation by first
We get r=10% Alternative method:
Interest in last two year= 29282-24200= 5082
find % interest in last two year= 5082 × 100/24200= 21%
so interest time= 2 year last
% rate= 21/2= 10% per annum
In what ratio tea of Rs.40 per kg be mixed with 10kg tea of Rs.32 per kg, so that cost price of mixture is Rs.37 per kg?
There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the present price of the article is Rs.2288, then what was the price 3 years ago?
Let the price of the article initially be rs.100
In the 1st year, price of the article=100+30=130
In the 2nd year, price=130=20% of 130=130-26=104
In the 3rd year, price=104+10% of 104=114.40
But present price=2288
Required price=2288*100/114.4
=2000
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