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Rohan purchased a car for Rs. 250000 and sold it for Rs. 348000. What is the percent profit the made on the car?
Cost price of car = Rs. 250000 Selling price of car = 348000 Profit= selling price – cost price Profit = 348000- 250000 = 98000 % profit = 9800 × 100/ 250000 = 39.20 %
461 + 462 + 463 + 464 is divisible by
461 + 462 + 463 + 464 = 461 (1 + 4 + 42 + 43 ) = 461 (1 + 4 + 16 + 64) = 461 (85) = 461 (17 × 5) Clearly 17 is a factor of 461 + 462 + 463 + 464 Hence it will be divisible by 17.
If x sin 60 ° tan 30 ° – tan245 ° = cosec 60 ° cot 30 ° – sec245 °, then x =
x sin 60 ° tan 30 ° – tan245 ° = cosec 60 ° cot 30 ° – sec245 °,
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If the total annual expend true of family B is Rs. 10,000 then money spent on clothes during the year is
Family B spent (60 - 45 = 15%) Total annual expenditure = Rs. 10000 Hence expenditure of family B in clothes = 15% of 10000
What fraction of the total expenditure is spent on Education in family A?
Family a spent (65 – 45 = 20%) in education Hence its fraction = 20/100 = 1/5
If the total annual expenditure of family A is Rs. 30,000 then money spent on food, clothes and house rents is.
Expenditure of A in Food = 30% Expenditure of A in clothes = (45 – 30 = 15%) Expenditure of A in house rent = (85 – 70 = 15%) Hence money spent on food, clothes and house rents by A is = 30 + 15 + 15 = 60% Total annual expenditure by family A = Rs. 30000
Hence 60% of 30000 =
If the total annual expenditure of family B is Rs. 20,000, then the amount spent by family B in education is ……
% of expenditure of family B in education is (80 – 60) = 20% Hence amount of expenditure in education = {(20,000*20)/100} = 4000
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