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IBPS PO 2018 Aptitude Test - 9
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IBPS PO 2018 Aptitude Test - 9
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  • Question 1/10
    1 / -0

    DIRECTIONS : What will come in place of the question mark (?) in the following questions?

    45% of 6400 - ? % of 4800 = 17 × 29 – 157

    Solutions

    45% of 6400 - ? % of 4800 = 17 × 29 – 157

    2880 - ? × 48 = 336

    ? × 48 = 2880 – 336 = 2544

    ? = 53

     

  • Question 2/10
    1 / -0

    DIRECTIONS: Find the missing term in the following series.

    46, 57, 81, 120, ?, 251

    Solutions

    46 + 11 × 1 = 46 + 11 = 57

    57 + 12 × 2 = 57 + 24 = 81

    81 + 13 × 3 = 81 + 39 = 120

    120 + 14 × 4 = 120 + 56 = 176

    176 + 15 × 5 = 176 + 75 = 251

     

  • Question 3/10
    1 / -0

    A vessel contains 16 litres solution of wine having 60% alcohol. How many litres of water is to be added to this solution, so that alcohol becomes 40% in the resultant solution?

    Solutions

    In 16 litres of solution, quantity of alcohol = 60% of 16 = 9.6 litres

    Now this 9.6 litres = 40% of resultant solution

    Therefore, resultant solution = 9.6/0.4 litres = 24 litres

    So, water added = 24 – 16 = 8 litres

     

  • Question 4/10
    1 / -0

    Area of a square P is 1024 m2. Side of square Q is 4 m more than the side of the square P. What is 60% of the difference between their perimeters?

    Solutions

    Area of square P = 1024 m2

    Side of square P =   = 32 m

    Side of square Q = 32 + 4 = 36 m

    Difference between their perimeters = 4(36 – 32) = 16 m

    Required % = 60 % of 16 m = 9.6 m

     

  • Question 5/10
    1 / -0

    The average age of all the seven children in a family is 10 years. If the age of the eldest person of the family is included, then the average age becomes 19 years. What is the age of the eldest person?

    Solutions

    Let the age of the eldest person of the family be ‘x'. As the average age of seven children is 10 years and all the eight together is 19 years.

    ⟹ 7 (10) + x = 8 × 19

    ⟹ 70 + x = 152

    ⟹ x = 152 – 70 = 82.

     

  • Question 6/10
    1 / -0

    Five years ago, the ages of Bali and Geeta were in the ratio of 3 : 4. Ten years hence the respective ratio of their ages will be 6 : 7. What is the difference between their present ages?

    Solutions

    Let the ages 5 years ago were 3x and 4x.

    Ages 10 years hence will be (3x + 15) and (4x + 15)

    Therefore, (3x + 15)/(4x + 15) = 6/7

    7(3x + 15) = 6(4x + 15)

    21x + 105 = 24x + 90

    3x = 15

    x = 5

    The difference between their ages = 4x – 3x = x = 5  years.

     

  • Question 7/10
    1 / -0

    Three sides of a triangular field are 7 meters, 25 meters and 24 meters. If it is to be excavated and leveled at the rate of Rs. 130 per square meter, then what is the total cost of the work?

    Solutions

    Given dimensions fulfill the condition of pythagoras theorem- 

    Thus, 

    7^2+24^2= 25^2

    so 

    h=25

    B=7

    Area= 1/2 *7*24= 84 m^2

    excavated and leveled at the rate = Rs. 130 per square meter

    thus 

    Total Cost =  84×130 = 10920 Rs.

    Alternate solution-  

    Area of triangle calculated by Heron's formula. 


     a=7 m

     b=25 m

     c= 24m 

    S= a+b+c/2

      = (7+25+24)/2

       = 56/2= 28

     

  • Question 8/10
    1 / -0

    A bowl contains 4 red balls, 3 blue balls and 5 yellow balls. If three balls are drawn at random, the probability that the balls drawn are of different colors is?

    Solutions

     

  • Question 9/10
    1 / -0

    A boat travelled 40 km downstream and 20 km upstream in 6 hours. The boat travelled another 56 km downstream and 34 km upstream in 9 hours. What is the speed of the water?

    Solutions

    Let the speed of downstream = SD kmph

    and speed of upstream  = SU kmph

    Then, (40/SD) + (20/SU) = 6---------(1)

    (56/SD) + (34/SU) = 9--------(2)

    By, 5 x eq(2) – 7 x eq(1) 

    30/SU= 3

    SU= 10 kmph

    now from eq (1),  (40/SD) + 2 = 6

    SD = 10  kmph

    speed of water = (SD– SU)/2 = (10 – 10)/2 = 0 kmph 

     

  • Question 10/10
    1 / -0

    A and B invested Rs.40,000 and Rs.50,000 respectively in a business. B left the business with his money after 4 months and after 2 more months he rejoins the business with a capital of Rs.60,000. At the end of the first year they earned a profit of Rs. 1,560. What is the share of A in the profit?

    Solutions

     

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