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Algebra Test 497
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Algebra Test 497
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  • Question 1/10
    1 / -0.25

    If  = 10, what is the value of ?
    Solutions
    x + 1/x = 10

    On squaring both sides, we get

    x2 + 1/x2 + 2 = 100

    x2 + 1/x2 = 98

    Again on squaring on both sides, we get

    x4 + 1/x4 + 2 = 9604

    x4 + 1/x4 = 9602

    Hence, option B is the correct answer.

  • Question 2/10
    1 / -0.25

    Simplify the following expression.

    (3x + 5)2 + (3x – 5)2

    Solutions

    Given Expression (3x + 5)2 + (3x – 5)2

    9x2 + 25 +15x + 9x2 +25 - 15x

    2(9x2+25)

    Hence, option D is the correct answer.

  • Question 3/10
    1 / -0.25

    Ten refrigerators and four mobile phones together cost ₹2,10,000 while six refrigerators and two mobile phones together cost ₹1,22,000. The cost (in ₹) of one refrigerator and two mobile phones is:

    Solutions
    According to the question:

    10R + 4M = 210000

    5R + 2M = 105000     ……. (i)

    6R + 2M = 122000     ……. (ii)

    By subtracting equation (i) from (ii), we get

    R = 17000

    By putting the value of R in equation (i), we get

    5(17000) + 2M = 105000

    2M = 20000

    M = 10000

    Cost of one refrigerator and two mobile phones

    = 17000 + 2(10000) = 37000

    Hence, option A is the correct answer.

  • Question 4/10
    1 / -0.25

    If 5x + y = 17 and xy = 6, then what is the value of 125x3 + y3 ?
    Solutions

    5x + y = 17

    xy = 6

    we know that,

    125x3 + y3 = (5x)3 + y3

    =

    = 4913 – 1530

    = 3383

  • Question 5/10
    1 / -0.25

    What is the value of a2 + b2 + c2 – 2ab – 2bc + 2ca ?
    Solutions

    a2 + b2 + c2 – 2ab – 2bc + 2ca

    we know that,

    (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

    So,

    (a – b + c)2 = a2 + b2 + c2 – 2ab – 2bc + 2ca

  • Question 6/10
    1 / -0.25

    If a3 = b3 + 988 and a – b = 4, then what is the value of 2a2 + 2ab + 2b2 ?
    Solutions

    a3 = b3 + 988

    a3 - b3 = 988

    or, (a – b)(a2 + ab + b2)=988

    or, 4(a2 + ab + b2) = 988

    or, 2(a2 + ab + b2) = 988/2 = 494

    (2a2 + 2ab + 2b2) = 494

  • Question 7/10
    1 / -0.25

    If  then what is the value of
    Solutions
     We know that, if x + 1/x = n, then x2 + 1/x2 = n2 – 2

    Now, a + 1/a = 8

    a2 + 1/a2 = (8)2 – 2 = 64 – 2 = 62

    a4 + 1/a4 = (62)2 – 2 = 3844 – 2 = 3842

    Hence, option C is the correct answer.

  • Question 8/10
    1 / -0.25

    What is the value of (a + b + c) {(a -b)2 + (b -c)2 + (c-a)2}?
    Solutions

    =

    =

    =

    =

    =

    Hence, option B is the correct answer.

  • Question 9/10
    1 / -0.25

    What is the value of (a2 + b2 + 4c2 – ab – 2bc – 2ca) (a + b + 2c)?
    Solutions

    (a2 + b2 + 4c2 – ab – 2bc – 2ca) (a + b + 2c)

    = (a + b + 2c) {(a)2 + (b)2 + (2c)2 – a × b – b × 2c – 2c × a}

    We know that,

    Here x = a, y = b and z = 2c

    = (a + b + 2c) {(a)2 + (b)2 + (2c)2 – a × b – b × 2c – 2c × a}

    = (a)3 + (b)3 + (2c)3 – 3 × a × b × 2c

    = a3 + b3 + 8c3 – 6abc

    Hence, option D is the correct answer.

  • Question 10/10
    1 / -0.25

    If , then what is the value of x7 + x–7 + x2 + x–2 ? (x < 0)
    Solutions

    x7 + x–7 + x2 + x–2

    = (-1)7 + (-1)–7 + (-1)2 + (-1)–2

    = - 1 – 1 + 1 + 1 = 0

    Hence, option D is the correct answer.

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