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We know that,
LCM × HCF = Product of the numbers
Or, 126 × 9 = 18 × other number
Or, other number = = 63
Hence, option A is the correct answer.
Let the numbers be 2x,3x,5x and 7x
HCF of 2x,3x,5x and 7x = x
x = 6
largest number = 7x = 7×6 = 42
Smallest number = 2x = 2×6 = 12
Sum of the squares of the largest and the smallest numbers = 422 + 122 = 1764 + 144 = 1908
18 = 2 × 32
21 = 3 × 7
24 = 23 × 3
LCM of 18,21 and 24 = 23 × 32 × 7 = 504
Five digits smallest number = 10000
When 10000 is divide by 504 remainder is 424 (504 × 19 + 424)
Required number = 10000 + (504 – 424) = 10080
15 = 3×5
24 = 23×3
28 =22×7
32 =25
LCM of 15, 24, 28 and 32 =25×3×5×7 = 3360
According to the option,
Required number = 3360 × 3 + 7 =10087
Let the HCF of two numbers be x
LCM of two numbers = 56x
Given:
x + 56x = 1710
57x = 1710
x = 30
HCF of the two numbers = 30
LCM of the two numbers = 56x = 56 × 30 = 1680
We know that:
First number × second number = LCM × HCF
240 × second number = 1680 × 30
Second number =
Second number = 210
Therefore, the other number is 210
Hence, option D is correct.
Let the two numbers be 9x and 13x
Given, HCF of 9x and 13x = x = 6
First number = 9x = 9 × 6 = 54
Second number = 13x = 13 × 6 = 78
⇒ 54 × 78 = LCM × 6
⇒ LCM =
⇒ LCM = 702
Therefore, the LCM of both numbers is 702.
Hence, option C is correct.
The greatest number by which when 448, 678 and 908 are divided, the remainder in each case is 11 = HCF of (448 - 11), (678 - 11) and (908 - 11)
x = HCF of (437, 667 and 897)
x = 23
Therefore, required remainder when 147 is divided by 23 = = 9 remainder
Let one number be x
Other number = 140 – x
(x) × (140 - x) = 240 × 20
140x – x2 = 4800
x2 – 140x + 4800 = 0
x2 – 80x – 60x + 4800 = 0
x(x - 80) – 60(x - 80) = 0
(x - 60)(x - 80) = 0
x = 60, 80
If, x = 60
Other number = 140 – 60 = 80
If, x = 80
Other number = 140 – 80 = 60
Therefore, the smaller number = 60
Hence, option A is correct.
48 × 144 = LCM × 48
⇒ LCM = 144
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