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LCM & HCF Test 493
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LCM & HCF Test 493
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  • Question 1/10
    1 / -0.25

    The HCF and LCM of two numbers are 9 and 126 respectively. If one of the number is 18, then what is the other number?

    Solutions

    We know that,

    LCM × HCF = Product of the numbers

    Or, 126 × 9 = 18 × other number

    Or, other number =  = 63

    Hence, option A is the correct answer.

  • Question 2/10
    1 / -0.25

    Four numbers are in the ratio 2 : 3 : 5 : 7 and their HCF is 6. What is the sum of the squares of the largest and the smallest numbers?


    Solutions


    Let the numbers be 2x,3x,5x and 7x


    HCF of 2x,3x,5x and 7x = x


    x = 6


    largest number = 7x = 7×6 = 42


    Smallest number = 2x = 2×6 = 12


    Sum of the squares of the largest and the smallest numbers = 422 + 122 = 1764 + 144 = 1908



  • Question 3/10
    1 / -0.25

    Find the least number of five digits which is exactly divisible by 18, 21 and 24 .


    Solutions


    18 = 2 × 32


    21 = 3 × 7


    24 = 23 × 3


    LCM of 18,21 and 24 = 23 × 32 × 7 = 504


    Five digits smallest number = 10000


    When 10000 is divide by 504 remainder is 424 (504 × 19 + 424)


    Required number = 10000 + (504 – 424) = 10080



  • Question 4/10
    1 / -0.25

    What is the least number which when decreased by 7 is divisible by 15, 24, 28 and 32?
    Solutions

    15 = 3×5

    24 = 23×3

    28 =22×7

    32 =25

    LCM of 15, 24, 28 and 32 =25×3×5×7 = 3360

    According to the option,

    Required number = 3360 × 3 + 7 =10087

  • Question 5/10
    1 / -0.25

    LCM of two numbers is 56 times their HCF, with the sum of their HCF and LCM being 1710. If one of the two numbers is 240, then what is the other number?
    Solutions

    Let the HCF of two numbers be x

    LCM of two numbers = 56x

    Given:

     x + 56x = 1710

     57x = 1710

     x = 30

    HCF of the two numbers = 30

    LCM of the two numbers = 56x = 56 × 30 = 1680

    We know that:

    First number × second number = LCM × HCF

     240 × second number = 1680 × 30

     Second number =

     Second number = 210

    Therefore, the other number is 210

    Hence, option D is correct.

  • Question 6/10
    1 / -0.25

    The ratio of two numbers is 9 : 13 and their HCF is 6 . Their LCM is:
    Solutions

    Let the two numbers be 9x and 13x

    Given, HCF of 9x and 13x = x = 6

    First number = 9x = 9 × 6 = 54

    Second number = 13x = 13 × 6 = 78

    We know that:

    First number × second number = LCM × HCF

    54 × 78 = LCM × 6

    LCM =

    LCM = 702

    Therefore, the LCM of both numbers is 702.

    Hence, option C is correct.

  • Question 7/10
    1 / -0.25

    Let x be the greatest number by which when 448, 678 and 908 are divided, the remainder in each case is 11. When 147 is divided by x, the remainder is:
    Solutions

    The greatest number by which when 448, 678 and 908 are divided, the remainder in each case is 11 = HCF of (448 - 11), (678 - 11) and (908 - 11)

    x = HCF of (437, 667 and 897)

    x = 23

    Therefore, required remainder when 147 is divided by 23 =  = 9 remainder

    Hence, option C is correct.

  • Question 8/10
    1 / -0.25

    The sum of two numbers is 140. If their LCM is 240 and HCF is 20, then find the smaller number.
    Solutions

    Let one number be x

    Other number = 140 – x

    We know that:

    First number × second number = LCM × HCF

     (x) × (140 - x) = 240 × 20

     140x – x2 = 4800

     x2 – 140x + 4800 = 0

     x2 – 80x – 60x + 4800 = 0

     x(x - 80) – 60(x - 80) = 0

     (x - 60)(x - 80) = 0

     x = 60, 80

    If, x = 60

    Other number = 140 – 60 = 80

    If, x = 80

    Other number = 140 – 80 = 60

    Therefore, the smaller number = 60

    Hence, option A is correct.

  • Question 9/10
    1 / -0.25

    Since the HCF of (48, 144) = 48, therefore the LCM of (48, 144) =?
    Solutions

    We know that:

    First number × second number = LCM × HCF

    48 × 144 = LCM × 48

    LCM = 144

    Hence, option C is correct.

  • Question 10/10
    1 / -0.25

    If a number is multiplied by 22 and the same number is added to it, then we get a number that is half the square of that number. Find the number.
    Solutions
    Let the no. be
    A.T.Q.



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