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∴ Total work = LCM of 4 and 9 = 36 units
Efficiency of A = 36/4 = 9
Efficiency of B = 36/9 = 4
They both work on alternate days, starting with B.
∴ Work done by B and A in first two days
= 4 + 9 = 13 units
2 days → 13 units
4 days → 26 units
Work done by B on 5th day = 4 units
∴ Remaining work = 36 – 26 – 4 = 6 units
Time taken by A to do remaining work = 6/9 = 2/3 days
∴ Total time = 5 + 2/3
= 5 days
Hence, option B is the correct answer.
∴ Total work = LCM of 4, 6 and 18 = 36 units
Efficiency of R = 36/4 = 9
Efficiency of S = 36/6 = 6
Efficiency of T = 36/18 = 2
Time taken by them together to complete the work
= 36/[9 + 6 + 2]
= 2.12 days
∴ Total work = LCM of 5 and 10 = 10 units
Efficiency of A = 10/5 = 2
Efficiency of B = 10/10 = 1
∴ Work done by B in 8 days = 1(8) = 8 units
Remaining work = 10 – 8 = 2 units
Time taken by A and B to complete the 2 units work
= 2/(2+1) = 2/3 days
∴ A leave the work after 2/3 days.
Hence, option A is the correct answer.
∴ Total work = LCM of 18 and 12 = 36 units
Efficiency of A = 36/18 = 2
Efficiency of B = 36/12 = 3
Work done by B in 4 days = 3(4) = 12 units
Remaining work = 36 – 12 = 24 units
Time taken by A to complete the remaining work
= 24/2 = 12 days
Time taken by X = 9 days
Time taken by Y = 36 days
Total work = L.C.M(9, 36) = 36 units
Efficiency of X = 36/9 = 4 units
Efficiency of Y = 36/36 = 1 unit
According to question,
(X+Y) 2 days work = 4 + 1 = 5 units
(X+Y) 14 days work = 5 ×
Remaining work = 36 – 35 = 1 unit
Time taken by X to complete the remaining work = 1/4 days
Total time taken = 14 +1/4 = days
Hence, option D is the correct answer.
Given,
4 women = 6 boys
Ratio of efficiences of a woman and a boy = 3 : 2
Total work = 2 × 60 = 120 days
Time taken by 5 women = 120/(5×3) = 8 days
Hence, option C is the correct answer.
Let the total work be 100 units(LCM of 20 and 25).
Efficiency of (P +Q) = 100/20 = 5 units/day
Efficiency of P = 100/25 = 4 units/day
Efficiency of Q = 5 – 4 = 1 unit/day
Time taken by Q alone to complete the work = 100/1 = 100 days
"Hence, option B is the correct answer."
Total work = 60 × 40 = 2400 units
First 10 days work done by 60 men = 60 × 10 = 600 units
Next 10 days work done by 55 men = 55 × 10 = 550 units
Next 10 days work done by 50 men = 50 × 10 = 500 units
Next 10 days work done by 45 men = 45 × 10 = 450 units
Remaining work = 2400 – (600 + 550 + 500 + 450) = 2400 – 2100 = 300 units
Time taken by 40 men to complete the remaining work = = 7.5 days
Total time = 10 + 10 + 10 + 10 + 7.5 = 47.5 days
Let the total work be 72 units(LCM of 36,18 and 24)
Efficiency of Raju = 72/36 = 2 units/hour
Efficiency of Angad = 72/18 = 4 units/ hour
Efficiency of Sumit = 72/24 = 3 units/ hour
Total efficiency of Raju, Angad and Sumit = 2 + 4 + 3 = 9 units/ hour
Required time = 72/9 = 8 hours
Let the total work be 30 units(LCM of 10 and 15)
Efficiency of Aarush and Maahi = 30/10 = 3 units/day
Efficiency of Aarush = 30/15 = 2 units/day
Efficiency of Maahi = 3 – 2 = 1 units/day
Time taken by Maahi to complete the work = 30/1 = 30 days
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